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Purpose 1.To study the effect of electric and magnetic fields on charged particles and to measure the charge to mass ratio of an electron.(1/2) m v2 = e V (3) Combining equations (2) and (3) gives e / m = ( 2 V / B2 r2) (4) Thus, when the accelerating voltage V, the magnetic field B, and the radius of the circular path r are known, the value of the e/m ratio can be computed and is given in units of C/kg by equation (4) if V is in volts, B in Teslas and r in meters.Theory When an electron moves in a magnetic field B whose direction is perpendicular to the velocity v of the particle, it is acted on by a force F perpendicular to B and v with a magnitude given by: |The force F is equal to the mass of the particle times the centripetal acceleration e v B = m v2 / r (2) where r is the radius of the circle and m is the mass of the electron.More practice in error analysis.2.F |

Original text

Purpose



  1. To study the effect of electric and magnetic fields on charged particles and to
    measure the charge to mass ratio of an electron.

  2. More practice in error analysis.
    Theory
    When an electron moves in a magnetic field B whose direction is perpendicular to
    the velocity v of the particle, it is acted on by a force F perpendicular to B and v with
    a magnitude given by:
    | F | = e v B (1)
    where e is magnitude of the charge of the electron. This force causes the particle to
    move in a circle in the plane perpendicular to the field. The force F is equal to the
    mass of the particle times the centripetal acceleration
    e v B = m v2 / r (2)
    where r is the radius of the circle and m is the mass of the electron. If the electron
    has been accelerated from rest through a potential difference V, then the kinetic
    energy is equal to the loss of potential energy.
    (1/2) m v2 = e V (3)
    Combining equations (2) and (3) gives
    e / m = ( 2 V / B2 r2) (4)
    Thus, when the accelerating voltage V, the magnetic field B, and the radius of the
    circular path r are known, the value of the e/m ratio can be computed and is given in
    units of C/kg by equation (4) if V is in volts, B in Teslas and r in meters.


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